Question

cosec4A-cosec2A=cot4A+cot2A​

Answer 1

Step-by-step explanation:

1/Sin4A - 1/Sin2A = Cos4A/Sin4A + Cos2A/Sin2A

Sin2A - Sin4A = Sin2A*Cos4A + Cos2A*Sin4A

-2Cos3A*SinA = Sin(2A+4A) = Sin6A = Sin(2*3A)

-2SinA*Cos3A = 2Sin3A*Cos3A

-SinA = Sin3A

Sin3A + SinA = 0

3SinA - 4Sin³A + SinA = 0

4SinA - 4Sin³A = 0

4SinA(1-Sin²A) = 0

4SinA*Cos²A = 0