cosecA +1/ cosec-1= 1+sinA /1-sinA
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rizwan98:
hi
hi
Answered by
1
from LHS
we know that
cosecA= 1/sinA
{(1/sinA)+1}/{(1/sinA)-1}
[(1+sinA)/sinA ]×[sinA/(1-sinA)]
= (1+sinA)/(1-sinA)
=RHS
we know that
cosecA= 1/sinA
{(1/sinA)+1}/{(1/sinA)-1}
[(1+sinA)/sinA ]×[sinA/(1-sinA)]
= (1+sinA)/(1-sinA)
=RHS
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