Question

cosecA-1/cosecA+1=1-sinA/cosA​

Answer 1

Answer:

LHS = (cosecA-1)/(cosecA+1)

= (1/sinA - 1) / (1/sinA + 1)

=(1 - sinA)/ (1+ sinA)

={(1-sinA)*(1+sinA)} / {(1+sinA)*(1+sinA)}

={(1 - sin^2 A)} / (1+sinA)^2

= (cos^2 A) / (1+sinA)^2

={cosA/(1+sinA)} ^ 2= RHS.

Hope this helps !!!!!

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Answer 2

cscA−1cscA+1=1−sinA1+sinA

LHS=cscA−1cscA+1=sinA1−1sinA1+1=sinA1−sinAsinA1+sinA=1−sinA1+sinA

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