Math, asked by vaibhav099, 1 year ago

coseca-1/coseca+1=cota-cosa/cota+cosa

Answers

Answered by Anonymous

15

Lhs = (cotA - cosA)/(cotA+cosA)

=(cosA/sinA - cosA)/(cosA/sinA + cosA)

=cosA(1/sinA - 1)/cosA(1/sinA + 1)

= (1/sinA -1)/(1/sinA+1)

=(cosecA-1)/(cosecA+1) since 1/sinA= cosecA

=rhs

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