Question

cosecA/cosecA-sinA=sec2A prove it

Answer 1

Step-by-step explanation:

CosecA / ( CosecA - Sin A) = sec²A

taking LHS

CosecA / ( CosecA - Sin A)

( 1/ SinA ) / ( 1 / SinA - SinA)

( 1/ SinA ) / {( 1 - Sin² A)/ SinA}

(1/ SinA ) / {(Cos²A)/SinA}

(1/ SinA * Sin A) / Cos² A

1 / Cos²A

Sec² A

hence proved

LHS = RHS