( cosecA+cotA ) ( 1-cosA ) = sinA
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Answer:
(1/sinA+cosA/sinA)(1-cosA)
(1+cosA/sinA)(1-cosA)
(1+cosA)(1-cosA)/sinA
(1^2-cosA^2)/sinA
sinA^2/sinA. ==.(sinA^2+cosA^2=1)
sinA
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Step-by-step explanation:
(cosecA+cotA)(1-cosA)
(1-cosA)(cosecA+cotA)
=1(cosecA+cotA)-cosA(cosecA+cotA)
=cosecA+cotA-cosA×cosecA-cosA×cotA
=1/sinA+cosA/sinA-cosA×1/sinA-cosA×cosA/sinA
=1+cosA/sinA-(cosA/sinA-cos2A/sinA)
=1+cosA/sinA-(cosA-cos2A/sinA)
=1+cosA/sinA-(-cosA/sinA)
=1+cosA/sinA+cosA/sinA
1+cos2A/sinA
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