cosecA+cotA=1\cosecA-cotA
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Hey Friend :-)
Here is your answer
=> 1 / (cosecA - cotA) . . . . . . . . . . .multiply top & bottom by (cosecA + cotA)
=> (cosecA + cotA) /(cosec^2A - cot^2A) . . . . . . .use cosec^2A = 1 + cot^2A
=> (cosecA +cotA) / 1
=> cosecA + cotA
RHS = LHS
Hence, proofed.
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