Question

(cosecA-cotA)^2=1-cosA/1+cosA​

Answer 1

Step-by-step explanation:

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Answer 2

$( {cosecA - cotA})^{2} \\ \\ = ( { \frac{1 - cosA}{sinA} })^{2} \\ \\ = \frac{( {1 - cosA})^{2} }{ {sin}^{2} A} \\ \\ = \frac{( {1 - cosA})^{2} }{1 - {cos}^{2}A } \\ \\ = \frac{1 - cosA}{1 + cosA}$