Question

(cosecA-cotA)²=(1-cosA)/(1+cosA)​

Answer 1

Answer:

L.H.S.=(1/sinA-cosA/sinA^2

={(1-cosA)/sinA}^2

=(1-cosA)^2/sin^2A

=(1-cosA)^2/1-cos^2A

=(1-cosA)/(1+cosA)

=R.H.S.

Answer 2

Answer:

Answer in the attachment...

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