Question

(cosecA+cotA)^2=1+cosA/1-cosA​

Answer 1

the answer is in the pic above

Answer 2

$( {cosecA + cotA})^{2} \\ \\ = ( { \frac{1 + cosA}{sinA} })^{2} \\ \\ = \frac{( {1 +cosA})^{2} }{ {sin}^{2} A} \\ \\ = \frac{( {1 + cosA})^{2} }{1 - {cos}^{2}A } \\ \\ = \frac{1 + cosA}{1 - cosA}$