Question

cosecA-cotA=4/3 then sinA+cosA=?

Answer 1

Answer:

$cosec \alpha - \cot\alpha = \frac{4}{3} \\ \frac{1}{ \sin \alpha } - \frac{ \cos \alpha }{ \sin\alpha } = \frac{4}{3} \\ \frac{ \sin \alpha - \cos \alpha }{ { \sin\alpha }^{2} } = \frac{4}{3}$

hope its help u