Question

cosecA-cotA=4/3 then sinA+cosA=?

Answer 1

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Answer 2

cosecA-cotA=4/3. ------------(1)

cosec^2A-cot^2A=1

(cosecA+cotA)(cosecA-cotA)=1

cosecA+cotA=1/(cosecA-cotA)=1/(4/3)=3/4. -------(2)

Adding (1) and (2)

2cosecA= (4/3)+(3/4)=25/12

cosecA=25/24

sinA=24/25

cosA=7/25

sinA+cosA=(24/25)+(7/25)=31/25