Question

Coseca - Cota= 9
then i/sina+ 1/tan =?​

Answer 1

Answer:

1/9

Step-by-step explanation:

We know that Cosec²A = 1+Cot²A

∴ Cosec²A -Cot²A=1

or

(CosecA -CotA)(CosecA +CotA)=1

But CosecA -CotA= 9

∴ 9(CosecA +CotA)=1

∴ CosecA +CotA = 1/9