(CosecA-cotA)square=1-cosA/1+cosa
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Answered by
111
AnswEr :
• To Prove :
• Proof :
I'm taking RHS to Prove this Identity -
⠀⠀⠀⋆ Multiplying by 1 - cos(A) / 1 - cos(A)
⠀⠀⠀⋆ (a - b)² = a² + b² - 2ab
⠀⠀⠀⋆ (1 - cos²(A)) = sin²(A)
⠀⠀⠀⋆ 1 / sin²(A) = cosec²(A)
⠀⠀⠀⋆ cos²(A) / sin²(A) = cot²(A)
⠀⠀⠀⋆ cos(A) / sin²(A) = cot(A)cosec(A)
⠀⠀⠀⋆ (a² + b² + 2ab) = (a - b)²
⠀
Answered by
20
To prove :
LHS
LHS = RHS
Formula :
• a^2-b^2=(a+b)(a-b)
• csc@= 1/sin@
• cot@= cos@/sin@
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