CosecA=Sec3A where 0<3A<90
Then tan 2A is how much ?
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Answer:
tan2A = 1
Explanation:
Given cosecA = sec3A
=> cosecA = cosec( 90-3A)
=> A = 90 - 3A
=> A + 3A = 90
=> 4A = 90
=> A = 90/4
=> A = 45/2---(1)
Now ,
tan2A
= tan( 2× 45/2) [ from (1)]
= tan 45°
= 1
••••
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