Math, asked by THELEGENDRYGUY, 4 months ago

(cosecA - sin A)/(cosec A + sin A) = (sec^2 A - tan^2 A)/(sec^2 A + tan^2 A)
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Answered by Anonymous
34

reffer to the attachment

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Answered by vg592805
1

L.H.S. = (cosec A – sin A)(sec A – cos A). sec2 A

= (1/sin A – sin A). (1/cos A – cos A). 1/cos2 A

= (1 – sin2 A/sin A) × (1 – cos2 A/cos A) × 1/cos2 a

= cos2 A/sin A × sin2 A/cos A × 1/cos2 A

[∵ (1 – sin2 A) = cos2 A]

[∵ 1 – cos2 A = sin2 A]

= sin A/cos A = tan A

= R.H.S.

Hence proved.

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