Math, asked by nupurchapra, 1 year ago

cosecA- sinA/cosecA+ sinA = sec2A - tan2A/sec2A + tan2A

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Answered by vk22025vicky
5
answered thisTo Prove:-cosec A-sin Acosec A+sin A=sec2A-tan2Asec2A+tan2ALHScosec A-sin Acosec A+sin A=1sin A-sin A1sin A+sin A=1-sin2A1+sin2ADividing numerator and denominator by cos2A, we get=1cos2A-sin2Acos2A1cos2A+sin2Acos2A=sec2A-tan2Asec2A+tan2A=RHSHence Proved. I hope this answer is helpful to you
Answered by Destroyer48
18
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