cosecA- sinA (secA-cosA) = 1\ tanA +cotA
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Answered by
5
Step-by-step explanation:
lhs =cosecA ,-sinA ×secA-cosA
1/sinA-sinA (1/cosA-cosA)
cosA/sinA sinA/cosA
cotA. 1/ tanA
rhs=
Answered by
2
Step-by-step explanation:
here is the answer to your question...
let,
LHS
=cosecA-sinA(secA-cosA)
=1/sinA-sinA(1/cosA-cosA)
=1-sin^2A/sinA(1-cos^2A/cosA)
=cos^2A/sinA×sin^2A/cosA
=cosA×sinA
now RHS,
=1/tanA+cotA
=1/sin/cosA+cosA/sinA
=1/sin^2A+cos^A/sinA×cosA
=sinA×cosA
therefore,
RHS=LHS.
hence,proved.
...please mark as brainliest..
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