Question

(cosecA-sinA) (secA-cosA) =1/tanA+cotA​

Answer 1

Answer:

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Step-by-step explanation:

(cosecA-sinA) (secA-cosA) = (1 - sin²A)(1 - cos²A)/sinAcosA

                                            = cos²Asin²A/sinAcosA

                                            = sinAcosA ...............................................1

1/tanA+cotA = 1/(sinA/cosA+cosA/sinA).

                    = sinAcosA / (sin²A+cos²A)

                    = sinAcosA .........................................................................2

eqn1 = eqn2

Hence proved