Question

(cosecA-sinA) (secA-cosA)=1/tanA+cotA​

Answer 1

★Hope it will help you....!!!!

Answer 2

$\underline \mathbb{SOLUTION}$

$= > ( \frac{1}{ \sin(a) } - sina)$

$= > ( \frac{1 - {sin}^{2}a }{sina} ) \times ( \frac{1 - {cosa}^{2} }{cosa} )$

$= > \frac{cos {a}^{2} }{sina} \times \frac{sin {}^{2} a}{cos} = sina \times cosa$

$\bold\green{\underline{Now,Rhs,}}$

$= > \frac{1}{tana + cota} = \frac{1}{ \frac{sina}{cos} + \frac{cosa}{sina} }$

$= > \frac{1}{ \frac{sin {a}^{2} + {cos}^{2} a }{?} } = \frac{sinacosa}{ {sin}^{2} a + {cos}^{2} a}$

$\frac{sina \times cosa}{1}$

$\bold\red{\underline{LHS=RHS}}$

$\bold\green{\underline{Hence\:Proved}}$

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