Math, asked by shahpalak318, 21 days ago

(cosecA -sina
.

)(seca -cosa)=1/tana +Cota

Answers

Answered by nishtirumalaraju

0

Answer:

LHS=(cosecA-sinA)(secA-cosA)

=(1-sin²A)(1-cos²A)/sinAcosA

=cos²Asin²A/sinAcosA

=sinAcosA ---------------(1)

RHS=1/tanA+cotA

=1/[(sin²A+cos²A)/sinAcosA]

=sinAcosA ---------------(2)

From (1) and (2) ,we can say that

(cosecA-sinA)(secA-cosA)=1/tanA+cotA

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