Question

(CosecA -sinA) (secA- cosA) = 1/TanA + cotA...


its so urgent..

Answer 1

(cosec A - sin A)(sec A - cos A)
= ( 1-sin^2 A / sin A) ( 1-cos^2 A/cos A)
= ( cos^2 A / sinA )(sin^2 / cos A)
= sin A cos A

RHS = 1/tan A + cot A = 1/sin A/cos A + cos A/sin A
= 1/sin^2 A + cos^A / sin A cos A = sin A cos A

And hence,
LHS=RHS

Hence, proved