(cosecA-sinA)×(secA-cosA)
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Answer:
cosAsinA
Step-by-step explanation:
we have, (cosecA-sinA)(secA-cosA)
(1/sinA-sinA)(1/cosA-cosA)
{(1-sinA²A)/sinA}{(1-cos²A)/cosA}
{cos²A/sinA}{sin²A/cosA}
=> cosAsinA ...ans.
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Step-by-step explanation:
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