Question

(cosecA -sinA ) (secA-cosA) (tanA-cotA) = 1​

Answer 1

Answer:

= cos² . sinA/cos²A. sinA = 1R. H. S

Step-by-step explanation:

(cosecA-sinA) (secA-cosA) (tanA-cotA) = 1

(cosecA-sinA) (secA-cosA) (tanA+cotA)=1

L. H. S= (cosecA-sinA) (secA-cosA) (tanA+cotA)

=( 1/sinA - sinA) (1/cosA- cosA) (tanA+ 1/tanA)

= (1-sin²A/sinA) (1-cos²A/cosA)(tan²A+1/tanA)

= (cos²A/sinA)(sin²A/cosA)(sec²A/tanA)

= cosA. sinA. 1/cos²A :-devide sinA/cosA

=cosA. sinA. 1/cos²A multiply cosA/sinA

= cos²A. sinA/ cos²A. sinA = 1 R. H. S

Answer 2

Answer:

Pls refer to image below ( Correction in question there is +ve sign Between tanA and cotA)

Step-by-step explanation: