(cosecA- sinA)(secA-cosA)(tanA+cotA) =1
prove it
Answers
Answered by
1
=1/sinA-sinA)(1/CosA-Cosa)(SinA/CosA+CosA/SinA)
=(1-Sin^2A/SinA)(1-Cos^2A/CosA)(Sin^2A+Cos^2A/SinACosA)
=(Cos^2A/SinA)(Sin^2A/CosA)(1/SinACosA)
=Cos^2A×Sin^2A/Sin^2A×Cos^2A
=1 proved
Similar questions