Math, asked by kumnarivamshi12, 10 months ago

(cosecA-sinA) (secA-cosA) (tanA+cotA)

Answers

Answered by Pallabkumar

1

Step-by-step explanation:

(1/sinA-sinA) (1/cosA-cosA) (sinA/cosA+cosA/sinA)

cos²A/sinA×sin²A/cosA(sin²A+cos²A/cosA×sinA)

1

Answered by Kyash15

0

Answer:ans is avsjwgwosvshsjsvs.............. 1

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