Math, asked by shivamgoswami386, 9 months ago

(cosecA-sinA)(secA-cosA)(tanA-cotA)​

Answers

Answered by nancynamita
3

here is your answer

i hope it will help you

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Answered by Anonymous
0

Step-by-step explanation:

(CosecA-SinA) (SecA-CosA) (tanA-CotA)

(1-Sin²A)/SinA * (1-Cos²A)/CosA *(tan²A-1)/tanA

Cos²A/SinA * Sin²A/CosA * (tan²A-1)/tanA

SinA*CosA*( Sin²A-Cos²A)/Cos²A * CosA/SinA

SinA*CosA * (Sin²A-Cos²A)/SinA*CosA

(Sin²A - Cos²A)

(1 - 2Cos²A)

= -Cos2A

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