Math, asked by habibullakhan2006, 9 days ago

(cosecA-sinA)(secA-cosA)(tanA+cotA)

Answers

Answered by sohilbhujade02

1

Step-by-step explanation:

cosecA−sinA)(secA−cosA)(tanA+cotA)

=(sinA1−sinA)(cosA1−cosA)(cosAsinA+sinAcosA)

=sinA(1−sin2A)×cosA(1−cos2A)×cosAsinAsin2A+cos2A

=sinA(cos2A)×cosA(sin2A)×cosAsinA1=1

(cosecA−sinA)(secA−cosA)(tanA+cotA)=1

Answered by βαbγGυrl

16

Answer:

Refer the attachment:)

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