Math, asked by doreneroxanas, 2 months ago

Cosece+2cosec20/sece =

Answers

Answered by Anonymous
1

Answer:

Given expression is  

sin20  

 

3

​  

 

​  

−  

cos20  

 

1

​  

 

=2(  

sin20  

 

3

​  

/2

​  

−  

cos20  

 

1/2

​  

)

=2(  

sin20  

 

sin60  

 

​  

−  

cos20  

 

cos60  

 

​  

)

=2(  

sin20  

cos20  

 

sin60  

cos20  

−cos60  

sin20  

 

​  

)

=2(  

sin20  

cos20  

 

sin(60  

−20  

)

​  

)

=2  

sin20  

cos20  

 

sin40  

 

​  

 

=2×  

sin20  

cos20  

 

2sin20  

cos20  

 

​  

 

=4

Step-by-step explanation:

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