Question

coseco in term of seco​

Answer 1

Answer:

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Answer 2

Answer:

secA=

cosA

1

⇒cosA=

secA

1

sin

2

A+cos

2

A=1⇒sin

2

A=1−

sec

2

A

1

⇒sinA±

1−

sec

2

A

1

tanA=

sec

2

A−1

cotA=

tanA

1

=

sec

2

A−1

1

cscA=

sinA

1

=±

sec

2

A−1

sec

2

A

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