Cosectheta-cottheta=1/4 find value of cosectheta +cottheta
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Answered by
1
According to question,
Cosec theta - Cot theta = 1/4
Expanding it into cos and sin
1/Sin theta - Cos theta / Sin theta = 1/4
taking the denominator,
W get,
(1 - Cos theta) / Sin theta = 1/4
Now doing the reciprocal on both the sides
We get,
(Sin theta) / (1-Cos theta) = 4
Multiplying the numerator and the denominator of LHS with (1 +Cos theta)
we get,
Sin theta * (1 + Cos theta) / (1 - Cos theta) * (1 + Cos theta) = 4
We know,
(a+b) (a-b) = a^2 -b^2
So (1 + Cos theta) (1- Cos theta) = 1- Cos^2 theta
= Sin^ theta
Thus putting this term in the above equation,
Sin theta * (1 + Cos theta) / Sin^2 theta = 4
(1 + Cos theta) / Sin theta = 4
Separating the denominator,
1/Sin theta + Cos theta / Sin theta = 4
Cosec theta + Cot theta = 4
Thus, the value of Cosec theta + Cot theta is 4
I hope u get it.
Mark Brainliest!! BRO!!
Cosec theta - Cot theta = 1/4
Expanding it into cos and sin
1/Sin theta - Cos theta / Sin theta = 1/4
taking the denominator,
W get,
(1 - Cos theta) / Sin theta = 1/4
Now doing the reciprocal on both the sides
We get,
(Sin theta) / (1-Cos theta) = 4
Multiplying the numerator and the denominator of LHS with (1 +Cos theta)
we get,
Sin theta * (1 + Cos theta) / (1 - Cos theta) * (1 + Cos theta) = 4
We know,
(a+b) (a-b) = a^2 -b^2
So (1 + Cos theta) (1- Cos theta) = 1- Cos^2 theta
= Sin^ theta
Thus putting this term in the above equation,
Sin theta * (1 + Cos theta) / Sin^2 theta = 4
(1 + Cos theta) / Sin theta = 4
Separating the denominator,
1/Sin theta + Cos theta / Sin theta = 4
Cosec theta + Cot theta = 4
Thus, the value of Cosec theta + Cot theta is 4
I hope u get it.
Mark Brainliest!! BRO!!
Answered by
2
hey I m refering theta to be a
so we know cosec^2a-cot^2a=1
so(cosec a+cot a )(cosec a -cot a )=1
now cosec a +cot a (1/4)=1
so cosec a + cot a =4
so we know cosec^2a-cot^2a=1
so(cosec a+cot a )(cosec a -cot a )=1
now cosec a +cot a (1/4)=1
so cosec a + cot a =4
nandini2106:
hmm
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