Question

Cosecx(cosecx + cotx)
Find the integral of the above statement

Answer 1

$\textbf{Hey there}$!!


$\textbf{Solution}$:


I = ∫[cosecx(cosecx + cotx )].dx


I = ∫($cosec^{2}$x + cosecx . cotx).dx


I = ∫$cosec^{2}$x .dx + ∫cosecx.cotx.dx


Using indentities:

∫cosec^2 x.dx= -cotx

∫cosecx.cotx.dx = -cosecx


I = -cotx - cosecx + C


Where C is Arbitrary Constant.


#Be Brainly.

Answer 2

answer is in the required attachment