Question

coso÷1-sino=1+sino÷coso​

Answer 1

Step-by-step explanation:

cos 0 ÷ 1-sin0 = 1 + sin0 ÷ cos o

1 ÷ 1-0 = 1+0 ÷ 1

1÷1 =1÷1

1=1 (hence proved).

Answer 2

Answer:

Step-by-step explanation:

Coso ÷ 1- sino= 1+sino÷ coso

LHS

(coso÷1-sino)^2

Cos^2÷1-sin^2

We know that,

Coso^2=1+sino

1-sino^2=coso^2

So, 1+sino^2÷coso^2

RHS :-

( 1+sino÷coso)^2

1+ sino^2÷coso^2

So LHS=RHS