cospie values 1 to 100
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i used De Moivre's theorem to tackle this problem.
(1+i)=2–√(cos(π/4)+isin(π/4))
using the theorem,
(1+i)100=2–√(cos(π/4)+isin(π/4))100
after some calculations,
=250(cos(8n+1)25π+isin(8n+1)25π)
putting n=0,1,2,…,99,we get the required values. My solution is correct ?
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