Math, asked by rakshit9847, 6 months ago

cosQ/1+sinQ+1+sinQ/cosQ=2secQ​

Answers

Answered by pratyushh69
4

Step-by-step explanation:

cos (1+sin)

(1+sin) + cos

= cos2 + (1+sin)2

cos*(1+sin)

= cos2 + 1 + 2sin + sin2

cos*(1+sin)

we know that cos2 + sin2 = 1

= (1+1+2sin)

cos*(1+sin)

= (2+2sin)

cos*(1+sin)

= 2(1+sin)

cos*(1+sin)

= 2

cos

= 2sec

Answered by justpie8
0

Step-by-step explanation:

 \cos(q)  \div sinq + 1 +  \sin(q)  \div  \cos(q)  \\  \cos {}^{2} q + (1 + sinq) ^{2}  \div (sinq(1 + cosq) \\ cos ^{2} q + 1 + 2sinq + sin ^{2} q \div (sinq(1 + cosq) \\ 2(1 + sinq) \div (cosq(1 + sinq) \\ 2secq \: proved

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