cost-2cosxsin 2x - 2sin'x cast
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0
Answer:
x→0
lim
cosx−cos
2
x
sin2x+2sin
2
x−2sinx
=
x→0
lim
cosx−cos
2
x
2sinxcosx+2−2cos
2
x−2sinx
=2⋅
x→0
lim
cosx−cos
2
x
sinxcosx−sinx−(cos
2
x−1)
=2.
x→0
lim
cosx−cos
2
x
sinx(cosx−1)−(cosx−1)(cosx+1)
=2.
x→0
lim
cosx(1−cosx)
(cosx−1)(sinx−cosx−1)
=2.
x→0
lim
cosx
1−sinx+cosx
=2×2=4
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