Question

Cost a quadratic polynomial if zeros are 2 and -3

Answer 1

Answer:

(x^2-x-6)is the correct answer.

Step-by-step explanation:

$< {x}^{2} +{\alpha}x+{\beta}x + \alpha \beta >$

x^2 +2x-3x+(2×-3)

(x^2-x-6)

Answer 2

Step-by-step explanation:

a=2,b=-3

sum of zeroes= a+b

= 2-3=-1

product of zeroes = a×b

= 2×-3 =-6

the required quadratic polynomial is k(×^2-(a+b)x+ab)

where k is constant

k (×^2-(-1)×+(-6))

k (×^2+×-6)

put k=1

the required Quadratic polynomial is ×^2+×-6