cost of 10 orange and 12 chikoos is ruppes 28 but cost of 12 orange and 10 chikoos is ruppes 1 less ,than find the cost of 2 orange and 4 chikoos
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Answer:
let orange = x
and chikoss = y
a/q 10x + 12y =28 --------eq 1
Now
a\q 12x + 10y = (28-1) one less the previous price
12x + 10y = 27 ------ eq 2
now solve both the equation
multiple eq1 x12 and eq2 x10
subtract (ii) from (I)
120x + 144y = 336
-( 120x + 100y = 270)
-------------------------------------
44y = 66
y = 3/4 ------- 0.75 rupes
put value of x and find x
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