Math, asked by Ruparel, 1 year ago

Cost of 10 oranges and 12 mango

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Answered by Thatsomeone
2
let the cost of one orange be x

let the cost of one mango be y

10x+12y=28 ... (I)

12x+10y=27 ... (II)

by adding equations (I) &(II) we get,

22x+22y=55

2x+2y=5 ...(III)(dividing by 11)

now subtracting (I) from (II) we get,

2x-2y=-1 ... (IV)

by adding (III) &(IV) we get,

4x=4

x=1

substitute value of x in equation (III)

2×1+2y=5

2+2y=5

2y=3

y=3/2

the cost of one orange is Rs 1 and cost of one mango is Rs 3/2

2x+4y=2×1+4×3/2

=2+6

=8

the cost of 2oranges and 4 mangos is Rs 8
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