Math, asked by siddhokale2007, 2 months ago

Cost of 21 bananas and 21 oranges put together is equal to 28 apples. Instead of
buying 21 bananas and 21 oranges, in the same cost if Sachin wants to buy equal
number of all three fruits, find how many apples can Sachin buy?

Answers

Answered by dinapampania
2

Step-by-step explanation:

Cost of 21 bananas and 21 oranges put together is equal to 28 apples. ok so ,

let the cost of 21 bananas be - B

let the cost of 21 orange be - O

21 bananas + 21 oranges = 28 apples

  • 21B+21O=28A
  • 21 (B+O) = 28.A

= B+O = 28A

B+O = 28A 21

this is our first equation

now for the second equation

  • N .A+N.B+ N.O = 28.A
  • N (A+B+O) = 28A
  • N = 28 . A.

(A+B+O)

  • N = 28.A.

A + 28. A.

21

  • N = 28 .A × 21.

21.A + 28.A

  • N= 28 .A × 21

49.A

= 12

= he has to buy 12 (++)

hope it helps dude

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