Question

Cost of 6 identical articles is ₹(2x+3) and the cost of 10 similar articles is ₹(4x-5). Find the value ofx​

Answer 1

Answer:

15

Step-by-step explanation:

6 articles cost=2x+3

This implies 10 articles cost is [(10)(2x+3)]/6, which is equal to (4x-5), according to the question.

(20x+30)=6(4x-5)

Solve to get

20x+30=24x-30

60=4x

Implies, x=15.

Answer 2

Answer:

Given -

Cost of 6 articles is ₹( 2x + 3)

Cost of 10 similar articles is ₹ ( 4x - 5)

To Find -

The value of x

Solution -

$cost \: of \: 6 \: articles = (2x + 3)$

$cost \: of \: 1 \: article = \frac{(2x + 3)}{6}$

$cost \: of \: 10 \: article = (4x - 5)$

$cost \: of \: 1 \: article = \frac{(4x - 5)}{10}$

Equating 1) and 2) we get,

$\frac{(2x + 3)}{6} = \frac{(4x - 5)}{10}$

$10(2x + 3) = 6(4x - 5) \: cross \: multiplication$

$= > 20x + 30 = 24x - 30$

$= > 4x = 60$

$= > x = 15$

Thank You

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