Question

Cost of a table is Rs 100 more than cost of 3 chairs. The above statement can be expressed as a linear equation as if cost of a table is Rs x and cost of a chair is Rs. y.. (a) x-3y+ 100 = 0 (b) x + 3y + 100 = 0 (c) x +3y 100 =0 (d) x - 3y - 100 = 0




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Answer 1

Answer:

Step-by-step explanation:

Given that:

Cost of a table is Rs 100 more than cost of 3 chairs.

Cost of a table is Rs. x.

Cost of a chair is Rs. y.

To Express:

Above statement as a linear equation.

By unitary method.

Cost of a chair = Rs. y

Cost of 3 chairs = Rs. 3y

According to the question.

Cost of a table = Cost of 3 chairs + 100

Putting all the given values.

↠ x = 3y + 100

↠ x - 3y - 100 = 0

Hence,

The correct option is (d) x - 3y - 100 = 0.

Answer 2

$\large{\underline{\textsf{Solution-}}}$

Given that:

Cost of a table is Rs 100 more than cost of 3 chairs.

Cost of a table is Rs. x.

Cost of a chair is Rs. y.

To Express:

Above statement as a linear equation.

By unitary method.

Cost of a chair = Rs. y

Cost of 3 chairs = Rs. 3y

According to the question.

Cost of a table = Cost of 3 chairs + 100

Putting all the given values.

• => x = 3y + 100
• => x - 3y - 100 = 0

Hence,

The correct option is (d) x - 3y - 100 = 0.