Math, asked by loknathservices, 4 months ago


Cost of an article is Rs.1200 and the SP is 5/4 times of its CP. Find the SP and the profit or loss as percentage.​

Answers

Answered by Anonymous
11

Answer:

Given:-

Cost of the article:-1200 rs

SP=5/4 of the CP

To find:-

SP and profit or loss %

Solution:-

SP=5/4 x 1200=1500rs

Profit =SP-CP

=1500-1200

=300rs

Profit %

=\frac{Profit*100}{CP} \\

=\frac{300*100}{1200} \\

=25%

Answered by anindyaadhikari13
4

Required Answer:-

Given:

  • Cost of an article is ₹1200
  • SP is 5/4 times it's C.P.

To find:

  • Selling Price.
  • Profit or Loss Percentage.

Solution:

Given that,

CP = ₹1200

So,

SP = 5/4 × CP

= 5/4 × ₹1200

= ₹ 5 × 300

= ₹1500

As SP > CP,

There is a profit of ₹(1500 - 1200) rupees

= 300

Profit Percentage

= Profit/CP × 100%

= 300/1200 × 100%

= 100/4 %

= 25%

Answer:

  • Selling Price = ₹1500.00/-
  • Profit Percentage = 25%

Remember:

  • If SP > CP then there is a profit of rupees (SP - CP)
  • If CP > SP then there is a loss of Rupees (CP - SP)
  • Profit/Loss% = (Profit or Loss)/CP × 100%
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