Math, asked by rajvardhan23, 8 months ago

cost of levelling the ground at the rate of rupees 7 per sqm was rupees 32, 340 if 500 rotations of a road roller of length 2.1 m were needed them find the diameter of the roller used​

Answers

Answered by UdayrajSinghNegi
1

Total cost for levelling = 32,340 rs

Rate of levelling = 7 rs / m²

Are levelled = Total cost for levelling / Rate of levelling

= 32340 / 7 = 4620 m²

h = 2.1 m

Area levelled = area covered by road roller in 500 rotations

4620 = 500 x 2πrh

4620 = 500 x 2 x 22/7 x r x 2.1

4620 x 7 / (500 x 22 x 2 x 2.1) = r

r = 7 / (10 x 3)

d = 14 / (10 x 3)

d = 0.47 m (approx) : Ans

Hope I helped

Answered by sreramv23
0
I don’t know the answer but I’m sure that if u ask ur teacher she will help u
Similar questions