cost of levelling the ground at the rate of rupees 7 per sqm was rupees 32, 340 if 500 rotations of a road roller of length 2.1 m were needed them find the diameter of the roller used
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Total cost for levelling = 32,340 rs
Rate of levelling = 7 rs / m²
Are levelled = Total cost for levelling / Rate of levelling
= 32340 / 7 = 4620 m²
h = 2.1 m
Area levelled = area covered by road roller in 500 rotations
4620 = 500 x 2πrh
4620 = 500 x 2 x 22/7 x r x 2.1
4620 x 7 / (500 x 22 x 2 x 2.1) = r
r = 7 / (10 x 3)
d = 14 / (10 x 3)
d = 0.47 m (approx) : Ans
Hope I helped
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I don’t know the answer but I’m sure that if u ask ur teacher she will help u
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