Question

Cost of new refrigerator is ₹ 20000.its price depreciates at the rate of 10% per annum.find its price after 2 years?

Answer 1

Question :-

Cost of new refrigerator is ₹ 20000.its price depreciates at the rate of 10% per annum.find its price after 2 years.

Answer :-

It's price after 2 years is ₹ 24200.

Formula used :-

$\implies \: \boxed{ \bf{ amount = p \: { \bigg(1 + \frac{r}{100} \bigg) }^{t} }} \\ \\ \bf{here \: p \: is \: the \: principal \: value \: of \: object \:} \\ \bf{ r \: is \: rate \: and \: t \: is \: time \: }$

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Step - by - step explanation:-

According to the question,

$\star \: \bf{ p \: = 20000} \\ \star \bf{r \: = 10\% }\\ \star \bf{\: t \: = 2 \: years}$

Now using the given formula ,

$\star \: \bf{amount \: = 20000 { \bigg(1 + \frac{10}{100} \bigg)}^{2} } \\ \\ \implies \: \bf{ 20000 \times { \big( \frac{11}{10} \big) }^{2} } \\ \\ \implies \: \bf{ 20000 \times \frac{11}{10} \times \frac{11}{10} } \\ \\ \implies \: \bf{200 \times 121} \\ \\ \implies \: \boxed{\bf{ amount \: = 24200}}$

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