Question

cost of one dozen oranges is 45.
1) Find the cost of one score oranges.
(b) How many oranges can be purchased for 60?
Cost of five pizzas is 725 and six pastries is 210. If I want to purchase three
pizzas and 12 pastries, how much should I pay?​

Answer 1

1. required cost= 45/12= 3.75 rs

2. if 1 orange is 3.75 rs

then, no of orange in 60rs = 60/ 3.75 = 6000/375= 16 orange ....

3. cost of 5 pizzas = 725 rs

then, cost of 1 pizzas= 725/5= 145 rs

now, cost of 6 pastries= 210 rs

therefore, cost of 1 pastry= 210/6= 35 rs

according to question,

cost of 3 pizzas= 3× 145 = 435rs and cost of 12 pastries= 12× 35= 420rs

now, we should pay 855 rs to buy these......

Answer 2

Answer:

The cost of one score oranges is ₹ 75 and 16 oranges can be purchased by ₹ 60 and you should pay ₹ 855.

Step-by-step explanation:

1 dozen = 12

And, 1 score = 20

Cost of 12 oranges = ₹ 45

Cost of 1 orange = ₹ 45/12

Cost of 20 oranges = ₹ 45/12×20

= ₹ 45/3×5

= ₹ 15×5 = ₹ 75(answer).

In ₹ 45 no of oranges purchased = 12

In ₹ 1 no of oranges purchased = 12/45

In ₹ 60 no of oranges purchased = 12/45×60

= 12/3×4

= 48/3 = 16(ans).

Cost of 5 pizzas = ₹ 725

Cost of 1 pizza = ₹ 145

Cost of 3 pizzas = ₹ 145 × 3 = ₹ 435

Cost of 6 pastries = ₹ 210

Cost of 1 pastry = ₹ 210/6

Cost of 12 pastries = ₹ 210/6×12

= ₹ 210×2 = ₹ 420

Therefore, you should pay ₹ 435+420 = ₹ 855.