Question

cost of ploughing at the rate of rupees 10 per metre square is rupees 1,540. find the radius of circular field.

Answer 1

Answer:

Radius of the circular field is 7m.

Step-by-step explanation:

Cost of ploughing = total area x cost of poulghing per 1 ( or given ) metre .

In the given question,

Cost of ploughing per metre=  Rs 10 per m^2

Cost of ploughing the whole area = Rs 1540

= >  Total area x Rs 10 / m^2 = Rs 1540

= >  Total area = Rs 1540 / Rs 10 m^2

= >  Total area = 154 m^2

As the given field is circular in shape, it's area should be πr^2.

Let the radius of the field be a,

Area of the field = 154 m^2 ( from above )

= >  ( 22 / 7 ) x a^2 = 154 m^2

= >   a^2 = 154 x 7 / 22  m^2

= >   a^2 = 7 x 7 m^2

= >   a^2 = 7^2 m^2

= >   a = 7 m

Hence the radius of the circular field = 7 m.

Answer 2

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Radius of the circular field is

= 7m

Cost of ploughing

= Total area × cost of ploughing / 1 metre .

According to given question

Cost of ploughing per metre :-

=  Rs 10 per $\huge\bf m^{2}$

Cost of ploughing the whole area = Rs 1540

= >  $\huge\bf\frac{Total area x Rs 10}{m^{2} }$ = Rs 1540

= >  Total area = $\huge\bf\frac{1540}{10m^{2} }$

= >  Total area = 154 $\huge\bfm^{2}$

Field is circular in shape :-

Area π$\huge\bf r^{2}$

Let the radius of the field be a

Area of the field = 154$\huge\bf m^{2}$  ( from up )

= >  $(\huge\bf \frac{22}{7})$ × $\huge\bf a^{2}$ = 154 $\huge\bf m^{2}$

= >   $\huge\bf a^{2}$ = 154 x $\huge\bf \frac{77}{2}$ $\huge\bf m^{2}$

= >    $\huge\bf a^{2}$ = 7 x 7   $\huge\bf m^{2}$

= >   $\huge\bf a^{2}$ =  $\huge\bf (7)^{2}$ $\huge\bf m^{2}$

= >   a = 7 m

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