Question

cost of two chairs and three tables is 3320 while the cost of one chair and two tables is 2020. find the cost of one chair

Answer 1

Let the cost of chair be x and cost of table be y.
2x+3y=3320
x+2y=2020 x=2020-2y
2(2020-2y)=3320
4040-4y=3320
4y=720
y=180Rs. x=720Rs
The ln,the cost of one chair is 720Rs.

Answer 2

Answer:

Step-by-step explanation:

Let the cost of chair be x

Let the cost of table be y

Soln:

2x+4y=3320......(1)

x+2y=2020.......(2)

Multiply eqs (2) by 2

Then

2x+4y=4040.....(3)

Subtract (3) from (1)

y=720

From(1)

2x+3y=3320

x=3320-3y÷2

x= 3320-3(720)÷2. {y=720}

x=1160÷2

x=580