Question

Cost of two pencils and three erasers is 18,
whereas the cost of one pencil and two erasers is 11. Find the cost of each pencil.
(a) 4
(b) 33
(c) 26
(d) 8




Please answer this question fastly......​

Answer 1

Step-by-step explanation:

Given:-

• Cost of 2 pencils and 3 erasers = ₹18
• Cost of 1 pencil and 2 erasers = ₹11

To find:-

Cost of each pencil.

Solution:-

Let the cost of one pencil be x and the cost of eraser be y.

Equating the given conditions,

we get,

2x + 3y = ₹18 (Equation 1)

x + 2y = ₹11 (Equation 2)

Multiplying equation 2 by 2,

we get,

2×(x + 2y) = 2 × ₹11

2x + 4y = ₹22 (Equation 3)

Subtracting equation 1 from equation 3, we get,

2x + 4y - (2x + 3y) = ₹22 - ₹18

2x + 4y - 2x - 3y = ₹4

y = ₹4

Thus, the cost of one eraser is ₹4.

Now, substituting the value of y in equation 2,

x + 2y = ₹11

x + 2×₹4 = ₹11

x + ₹8 = ₹11

x = ₹3

Thus, the cost of one pencil is ₹3.

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Answer 2

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Given:-

Cost of 2 pencils and 3 erasers = ₹18

Cost of 1 pencil and 2 erasers = ₹11

To find:-

Cost of each pencil.

Solution:-

Let the cost of one pencil be x and the cost of eraser be y.

Equating the given conditions,

we get,

2x + 3y = ₹18 (Equation 1)

x + 2y = ₹11 (Equation 2)

Multiplying equation 2 by 2,

we get,

2×(x + 2y) = 2 × ₹11

2x + 4y = ₹22 (Equation 3)

Subtracting equation 1 from equation 3, we get,

2x + 4y - (2x + 3y) = ₹22 - ₹18

2x + 4y - 2x - 3y = ₹4

y = ₹4

Thus, the cost of one eraser is ₹4.

Now, substituting the value of y in equation 2,

x + 2y = ₹11

x + 2×₹4 = ₹11

x + ₹8 = ₹11

x = ₹3

Thus, the cost of one pencil is ₹$3$