Question

Cost of two tables and three chairs of $705 the table cost $40 more than the chair. what is the price of the table and the chair?

Answer 1

Tables be X
Chairs be Y
2X+3Y=$705
X=Y+40[table cost $40 more than the chair]
sub X in  2X+3Y=$705
2(Y+40)+3Y=$705
5Y+80=705
5Y=625
Y=625/5
Y=125
Tables $125+40=$165===2*165=$330
Chairs $125===$125*3=$375
Total $705

Answer 2

Answer:

The cost of 1 chair is $125 and 1 table is $165.

Step-by-step explanation:

Let the cost of chair be x

Cost of 3 chair = 3x

Now we are given that  the table cost $40 more than the chair.

So, table's cost = x+40

Cost of 2 tables = 2(x+40)

Now we are also given that Cost of two tables and three chairs of $705

So, $3x+2(x+40)=705$

$3x+2x+80=705$

$5x=625$

$x=125$

Cost of 1 chair is 125

Cost of 1 table = 125+40 = 165

Hence the cost of 1 chair is $125 and 1 table is $165.